Potassium manganate(VII) titrations. In these redox titrations the manganate(VII) is the oxidising agent and is reduced to Mn 2+ (aq); The iron is the reducing agent and is oxidised to Fe 2+ (aq) and the reaction mixture must be acidified, to excess acid is added to the iron(II) ions before the reaction begins; The choice of acid is important, as it must not …
WhatsApp: +86 182217550733. Weigh a clean, dry 100 or 250 mL beaker. 4. Accurately weigh approximately 1.00 gram of iron powder into the beaker. Do not exceed 1.00 grams. 5. Measure 30 mL of 1.0 M CuSO4 solution into a graduated cylinder. Pour it into an Erlenmeyer flask, and heat gently to almost boiling. 6. Slowly add the hot CuSO4 solution to the beaker containing ...
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WhatsApp: +86 18221755073Hematite (iron ore) weighing $70.7 mat{~g}$ was placed in a flask whose volume was $53.2 mat{~mL}$. The flask with hematite was then carefully filled with water and weighed. The hematite and water weighed $109.3 mat{~g}$. The density of the water was $0.997 mat{~g} / mat{cm}^{3} .$ What was the density …
WhatsApp: +86 18221755073Hematite (iron ore) weighing 70.7 g 70.7 mat{~g} 70.7 g was placed in a flask whose volume was 53.2 m L 53.2 mat{~mL} 53.2 mL. The flask with hematite was …
WhatsApp: +86 18221755073A sample of iron ore, weighing 0.700 g, is dissolved in nitric acid.The solution is then diluted with water, following with sufficient concentrated aqueous ammonia, to quantitative precipitation the iron as F e (O H) 3.The precipitate is filtered, ignited and weighed as F e 2 O 3. If the mass of the ignited and dried precipitate is 0.541 g.What is the mass per cent …
WhatsApp: +86 182217550736) Hematite (an iron ore) weighing 70.7 g was placed in a graduated cylinder; the cylinder was then carefully Willed with water to a volume of 53.2 mL. The hematite and water weighed 109.3 g. The density of the water was 0.997 g/cm². What is the density of hematite? 7) How many protons, neutron and electrons are there in each isotope?
WhatsApp: +86 18221755073A strip of iron weighing 0.95g is placed in the flask and allowed to react with the sulfur. If the weight of the new compound is 77g, determine: (Fe = 55.85g/mol and S = 32.06g/mol) a. The mass of sulfur reacted = _____ b. The mass percent Fe and S based on the experiment %Fe = %S = c. The empirical formula of the compound.
WhatsApp: +86 18221755073Hematite (iron ore) weighing 70.7 g was placed in a flask whose volume was 53.2 mL. The flask with hematite was then carefully filled with water and weighed. The hematite and water weighed 109.3 g.
WhatsApp: +86 18221755073Question: 1.38 Some iron wire weighing 5.6 g is placed in a beaker and covered with 15.0 g of dilute hydrochloric acid. The acid reacts with the metal and gives off hydrogen gas, which escapes into the surrounding air. After reaction, the contents of the beaker weigh 20.4 g. What is the mass of hydrogen gas produced by the reaction?
WhatsApp: +86 18221755073VIDEO ANSWER: The information has been used. Let's figure out the density of the substance. The mass of the iron is 70.7 g. Yeah, that's correct. The water is equal to 100.3g. If we divide the water's mass by the volume, we get 38.6 g. The amount of
WhatsApp: +86 18221755073Hematite (iron ore) weighing $70.7 mat{~g}$ was placed in a flask whose volume was $53.2 mat{~mL}$. The flask with hematite was then carefully filled with water and weighed. The hematite and water weighed $109.3 mat{~g}$. The density of the water was $0.997 mat{~g} / mat{cm}^{3} .$ What was the density of the hematite?
WhatsApp: +86 18221755073Hematite (iron ore) weighing $70.7 mat{~g}$ was placed in a flask whose volume was $53.2 mat{~mL}$. The flask with hematite was then carefully filled with water …
WhatsApp: +86 18221755073The volume of the hematite is equal to the volume of the flask minus the volume of the water: [V_{hematite} = V_{flask} - V_{water} = 53.2cm^3 - 38.72cm^3 = …
WhatsApp: +86 18221755073Solution For Hematite (iron ore) weighing 70.7 g was placed in a flask whose volume was 53.2 mL. The flask with hematite was then carefully filled with water and weighed. The hematite and water weighe
WhatsApp: +86 18221755073A sample of iron ore weighing 0.2792 g was dissolved in dilute acid solution, and all the iron (III) was converted to iron (II) ions. The solution required 26.48 ml of 0.02315 M K2Cr2O7 (MW 294.18 g/mol) for titration. The redox reaction involved in the titration is given below. Calculate the percent by mass of iron in the ore.
WhatsApp: +86 182217550732 Hematite Iron ore weighing 707 g was placed in a flask The flask with hematite from CHM 101 at Prince Sultan University. AI Homework Help. ... Log in Join. 2 hematite iron ore weighing 707 g was placed in a. Doc Preview. Pages 4. Identified Q&As 17. Solutions available. Total views 8. Prince Sultan University. CHM. CHM 101. meow112211. 4/24 ...
WhatsApp: +86 18221755073Hematite (an iron ore) weighing 70.7g was placed in a graduated cylinder; the cylinder was then carefully filled with water to a volume of 53.dml. The hematite and water weighed 109.3g. ... 1000 4. (EC) 70.4g of hematite (iron ore) was placed in a flask whose maximum volume was 55.0 mL. The flask with hematite was then carefully filled …
WhatsApp: +86 18221755073A sample of iron ore weighing 0.2792 g was dissolved in dilute acid solution, and all the iron (III) was converted to iron (II) ions. The solution required 26.48 ml of 0.02315 M K2Cr2O7 (MW 294.18 g/mol) for titration. The redox reaction involved in the titration is given below. Calculate the percent by mass of iron in the ore.
WhatsApp: +86 18221755073A mass of iron ore weighing 0.2792g was dissolved in dilute acid and all the iron was converted to Fe2+(aq). The iron II solution required 23.30ml of 0.0194M …
WhatsApp: +86 18221755073Hematite (iron ore) weighing 71 g was placed in a flask whose volume was 55 mL. The flask with hematite was then carefully filled with water and weighed. The hematite and water weighed 109.0 g. Liquid Nitrogen boils at -320.8 °F. …
WhatsApp: +86 18221755073Hematite (iron ore) weighing 70.7 g was placed in a flask whose volume was 53.2 mL.The flask with hematite was then carefully filled with water and weighed. The hematite and water weighed 109.3 g.The density of the water was 0.997 0.997
WhatsApp: +86 18221755073Find step-by-step Chemistry solutions and your answer to the following textbook question: Hematite (iron ore) weighing $70.7 mat{~g}$ was placed in a flask whose volume …
WhatsApp: +86 18221755073A sample of iron ore weighing 0.740 g, containing 24% F e 2 O 3, is dissolved and the iron is reduced to F e 2 + by the addition of 25.0 mL of 0.05 M S n C l 2. The excess S n 2 + is oxidised to S n 4 + using 0.05 M H g C l 2. Volume of H g C l 2 used is:
WhatsApp: +86 18221755073Click here:point_up_2:to get an answer to your question :writing_hand:a sample of nano3 weighing 038g is placed in a 500ml volumetric flask the flask. Solve. Guides. Join / Login. Use app Login. 0. You visited us 0 times! Enjoying our articles? Unlock Full Access! Standard XII. ... $$ weighing $$0.83 g$$ is placed in a $$50 ml$$ volumetric ...
WhatsApp: +86 18221755073Text Solution, solved step-by-step: Hematite (iron ore) weighing $70.7 mat{~g}$ was placed in a flask whose... Transcript. 00:02 Using the information provided, let's …
WhatsApp: +86 18221755073A 15.5 g sample of sodium carbonate is added to a solution of acetic acid weighing 19.7 g. The two substances react, releasing carbon dioxide gas to the atmosphere. After reaction, the contents of the reaction vessel weigh 28.7 g. What is the mass of carbon dioxide given off during the reaction?
WhatsApp: +86 18221755073So the mass of the water was 38.6 g. The density of uh of water was given the questions .997 g per cm cubed there for the volume of the water is equal to 38.72. Mhm cubic centimeters. Yeah. So the volume of the hematite, yeah, is equal to the volume of the flask minus the volume of the water. The volume of the flask Is 53.2. Okay milliliters.
WhatsApp: +86 18221755073Find step-by-step Chemistry solutions and your answer to the following textbook question: A sample of iron ore weighing 0.2792 g, was dissolved in an excess of a dilute acid solution. All the iron was first converted to Fe(II) ions. The solution then required 23.30 mL of 0.0194 M $mat{KMnO}_4$ for oxidation to Fe(III) ions. Calculate the percent by mass of …
WhatsApp: +86 18221755073A sample of iron ore weighing $0.2792 mat{g}$ was dissolved in an excess of a dilute acid solution. All the iron was first converted to Fe(II) ions. The solution then required $23.30 mat{mL}$ of $0.0194 mat{M}$ KMnO_ for oxidation to Fe(III) ions. Calculate the percent by mass of iron in the ore.
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